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ArchivesRubik can be solved in 35qSubmitted by silviu on Wed, 03/22/2006 - 10:19.Let H be the group < U,D,L2,F2,B2,R2 > and let N be the subgroup of H that contains
all even elements in H.
I have run an exhaustive search on the coset space G/N and got the following table:
0q 1 1q 9 2q 68 3q 624 4q 5544 5q 49992 6q 451898 7q 4034156 8q 35109780 9q 278265460 10q 1516294722 11q 2364757036 12q 235188806 13q 28144The group N contains no elements of odd length and the maximum length is 24. » 3 comments | read more
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