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ArchivesRubik can be solved in 35qSubmitted by silviu on Wed, 03/22/2006 - 10:19.Let H be the group < U,D,L2,F2,B2,R2 > and let N be the subgroup of H that contains
all even elements in H.
I have run an exhaustive search on the coset space G/N and got the following table:
0q 1
1q 9
2q 68
3q 624
4q 5544
5q 49992
6q 451898
7q 4034156
8q 35109780
9q 278265460
10q 1516294722
11q 2364757036
12q 235188806
13q 28144
The group N contains no elements of odd length and the maximum length is 24.» 3 comments | read more
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