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Archives2 questionsSubmitted by mdlazreg on Thu, 02/21/2008 - 02:02.Hi,
I am asking for help to understand the second phase of the 2-phases algorithm. I do understand the first phase. My question is once we bring the scrambled cube to a position in the G1 = subgroup, how is this position taken to the Identity? Kociemba says the following in his website: In phase 2 the algorithm restores the cube in the subgroup G1, using only moves of this subgroup. It restores the permutation of the 8 corners, the permutation of the 8 edges of the U-face and D-face and the permutation of the 4 UD-slice edges. The heuristic function h2(a,b,c) only estimates the number of moves that are necessary to reach the goal state, because there are too many different elements in G1. » 7 comments | read more
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