Rubik can be solved in 35q

Let H be the group < U,D,L2,F2,B2,R2 > and let N be the subgroup of H that contains all even elements in H. I have run an exhaustive search on the coset space G/N and got the following table:

      0q             1
      1q             9
      2q            68
      3q           624
      4q          5544
      5q         49992
      6q        451898
      7q       4034156
      8q      35109780
      9q     278265460
     10q    1516294722
     11q    2364757036
     12q     235188806
     13q         28144

The group N contains no elements of odd length and the maximum length is 24. The position of length 24 is a local maxima. I have explained in my previous posts that when combining two solutions g an h and the phase 2 solution is a local maxima then the length of the total gh is less than or equal to L(g)+L(h)-2. Where L(g) means the length of g. This shows that two phase solutions based on the group N are maximum 35 quarter turns long.