Subgroups using basic moves
Submitted by mdlazreg on Wed, 03/20/2013 - 20:20.
In QTM, the whole cube is generated using U,D,R,L,F,B moves.
If we drop some moves we end up with some subgroups. The subgroups are:
I know the depth table for subgroups 1) 2) 3) and 4):
The subgroup 1) generated by "no move", has the following obvious table:
If we drop some moves we end up with some subgroups. The subgroups are:
1) I [the identity] 2) U 3) U,D 4) U,F 5) U,D,F 6) U,F,R 7) U,D,F,B 8) U,D,F,R 9) U,D,F,B,R
I know the depth table for subgroups 1) 2) 3) and 4):
The subgroup 1) generated by "no move", has the following obvious table:
Moves Deep arrangements (q only) 0 1 ------ 1The subgroup 2) generated only by the move U, has the following table:
Moves Deep arrangements (q only) 0 1 1 2 2 1 ------ 4The subgroup 3) generated by U,D has the following table:
Moves Deep arrangements (q only) 0 1 1 4 2 6 3 4 4 1 ------ 16The subgroup 4) generated by U,F has the following table:
Moves Deep arrangements (q only) 0 1 1 4 2 10 3 24 4 58 5 140 6 338 7 816 8 1,970 9 4,756 10 11,448 11 27,448 12 65,260 13 154,192 14 360,692 15 827,540 16 1,851,345 17 3,968,840 18 7,891,990 19 13,659,821 20 18,471,682 21 16,586,822 22 8,039,455 23 1,511,110 24 47,351 25 87 ---------- 73,483,200My question is, do we have similar numbers for the remaining subgroups? even partial numbers, or total arrangements for each group?